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Q1. The perimeter of an equilateral triangle with side 9 mm is
  • 1) 2.7 cm
  • 2) 0.027 cm
  • 3) 0.27 cm
  • 4) 27 cm

Solution

Length of one side of the equilateral triangle = 9 mm = 0.9 cm Perimeter of equilateral triangle = (0.9 + 0.9 + 0.9) = 2.7 cm
Q2. If there are 36 gems on a necklace and out of them  are red, then the number of red gems is 
  • 1) 14
  • 2) 9
  • 3) 7
  • 4) 12

Solution

Number of red gems = 
Q3.  is not equivalent to
  • 1)
  • 2)
  • 3)
  • 4)

Solution

A. 10 over 18 equals fraction numerator 10 divided by 2 over denominator 18 divided by 2 end fraction equals 5 over 9 B. 15 over 27 equals fraction numerator 15 divided by 3 over denominator 27 divided by 3 end fraction equals 5 over 9 C. 30 over 45 equals fraction numerator 30 divided by 15 over denominator 45 divided by 15 end fraction equals 2 over 3 D. 20 over 36 equals fraction numerator 20 divided by 4 over denominator 36 divided by 4 end fraction equals 5 over 9 Hence, 30 over 45is not equivalent to 5 over 9.
Q4. Rani poured  ml of curd in one glass and added 2 over 3 ml of water in it. The total quantity of mixture is?
  • 1) 5 over 3ml
  • 2) 10 over 3ml
  • 3) 3 ml
  • 4) 8 over 3ml

Solution

Total mixture is ml +2 over 3ml = 9 over 3ml 
Q5. If the cost of 12 pens is Rs.75 then the cost of 1 pen is:
  • 1) Rs. 7.50
  • 2) Rs. 6.25
  • 3) Rs. 5.50
  • 4) Rs. 6.50

Solution

Cost of one pen =Rs.75 over 12=Rs.6.25
Q6. Mary's car gets 44.8 miles per gallon on the highway. If her fuel tank holds 15.4 gallons, then how far can she travel on one full tank of gas?   

Solution

Distance covered by Mary's car with 1 gallon fuel = 44.8 miles   Capacity of her fuel tank = 15.4 gallons   Thus, distance travelled on one full tank of gas = 44.8 x 15.4   Multiply as you would multiply whole numbers    = 448 x 154   = 68992     Move 2 places from right to the left to place the decimal point because there is 1 decimal place in 44.8 and 1 decimal place in 15.4   i.e., 689.92     Thus, she can travel 689.92 miles on one full tank of gas.   
Q7. 8 tens + 8 ones + 8 tenths is greater than
  • 1) 9 tens + 8 ones + 8 tenths + 8 hundredths
  • 2) 8 hundred + 9 tens + 8 ones
  • 3) 8 tens + 8 ones
  • 4) 8 tens + 8 ones + 8 tenths + 8 hundredths

Solution

8 tens + 8 ones + 8 tenths = 88.8 (A) 8 tens + 8 ones = 88 (B) 8 tens + 8 ones + 8 tenths + 8 hundredths = 88.88 (C) 8 hundred + 9 tens + 8 ones = 898 (D) 9 tens + 8 ones + 8 tenths + 8 hundredths = 98.88 From above, 88.8 > 88 So, 8 tens + 8 ones + 8 tenths is greater than 8 tens + 8 ones which is option (A)
Q8. The sum of the shaded portions of the fractions is
  • 1)
  • 2)
  • 3)
  • 4)

Solution

Q9. Sunita bought 2 1 half litres of mango juice and 1 fourth litres of pineapple juice. The total quantity of juice bought by her is
  • 1) 9 over 8litres
  • 2) 11 over 2litres
  • 3) 9 over 4litres
  • 4) 11 over 4litres

Solution

Quantity of Mango juice = 2 1 halflitres Quantity of Pineapple juice = 1 fourthlitres Total quantity = 2 1 half plus 1 fourth space equals space 5 over 2 space plus space 1 fourth space equals space 10 over 4 space plus space 1 fourth space equals space 11 over 4 litres
Q10. Rahim buys 6 Kg of mangoes at the price of Rs. 12.5 per kg. He spent a total of  ____________.
  • 1) Rs. 95
  • 2) Rs. 100
  • 3) Rs. 85
  • 4) Rs. 75

Solution

Cost of one kg of mangoes = Rs. 12.5 Weight of mangoes bought = 6 kg Total money spent = Rs. (6 x 12.5) = Rs. 75
Q11. Five swimmers entered into a competition. Four of the swimmers have had their turns. Their timings are 9.8 sec, 9.75 sec, 9.79 sec, and 9.81 sec. What timing must the last swimmer set in order to win the competition?  

Solution

In order to win the competition, the last swimmer has to set a time less than the least timing set by other contestants.   For that, we have to compare the timings obtained by arranging them in the increasing order of magnitude.   i.e., 9.75 < 9.79 < 9.80 < 9.81   Since the least decimal value is 9.75, the last swimmer must set a time less than 9.75 sec, in order to win.    
Q12. An Italian sausage is 8 inches long. How many pieces of sausage can be cut from the 8-inch piece of sausage if each piece is to be two-third of an inch?

Solution

Since we are trying to find out how many two-thirds are there in 8, it is a division of fractions problem. So, dividing 8 by , we get = = Therefore, 12 pieces each of inches can be cut.
Q13. Sakshi read  of a novel consisting of 579 pages. How many pages are still left?
  • 1) 146
  • 2) 292
  • 3) 386
  • 4) 193

Solution

Number of pages read =2 over 3 cross times 579 equals 2 cross times 193 equals space 386 pages Thus, number of pages left = 579 - 386 = 193 pages
Q14. Equivalent fraction of 5 over 9 is:
  • 1)
  • 2)
  • 3)
  • 4)

Solution

 (Dividing numerator and denominator by 10) Thus, is equivalent to .
Q15. If the length of two rods is 9.75 m and 8.80 m then the difference between their lengths is
  • 1) 0.90 m
  • 2) 0.95 m
  • 3) 0.85 m
  • 4) 0.75 m

Solution

Difference = 9.75 - 8.80 = 0.95 m
Q16. LCM of the denominators of   and   is 
  • 1) 99
  • 2) 55
  • 3) 40
  • 4) 72

Solution

11 and 9 are prime numbers. Hence, LCM of 11 and 9 is 99. 
Q17. A chemist has several beakers full of different liquids that he will use to make a solution. The chemist records the amount of liquid in each beaker: 640.6 milliliters, 908.44 milliliters, 1.5553 liters, and 0.6 liters. How many milliliters of solution will the chemist have after he mixes together the liquids in the beakers?  

Solution

In order to add the measure of solutions, the amount of liquid in each beaker must have same units. Since the measures of all the beakers do not have the same units, we convert liters into milliliters to make all the units similar.  We know that :-        1 liter = 1000 milliliters  So,  1.5553 liters =  1555.30 milliliters  And  0.6 liters = 600 milliliters  Now, adding all the measurements we get,               2 1 1 1                640.60          +    908.44          +  1555.30          +    600.00             bottom enclose space space space space space space space space space space space space end enclose              3704.34              bottom enclose space space space space space space space space space space space space end enclose Thus, the chemist will get 3704.34 milliliters of solution after he mixes together the liquids in the beakers.    
Q18. An airplane covers 50 miles in hours. How many miles can the airplane cover in 5 hours?

Solution

This problem is a combination of division and multiplication of fractions. First, find out how many (1/5)ths are there in 5 by dividing 5 by i.e.  5 ÷ = = 25 Then, multiply 50 by 25 i.e. 50 x 25 = 1250 Thus, the airplane will cover 1250 miles in 5 hours.
Q19. It takes yards of material to make a shirt. How many yards of material will be required to make 6 shirts?

Solution

Material required to make 1 shirt =yards Material required to make 6 shirts = Thus, to make 6 shirts, yards of material will be required.
Q20. Sheela has  kg of wheat. She bought  kg more. The total quantity of wheat is 
  • 1)
  • 2)
  • 3)
  • 4)

Solution

Total quantity of whaet is given by    kg
Q21. 5 thousands + 3 hundreds + 1 tens + 5 ones + 7 tenths + 7 hundredths can be written as __________.
  • 1) 5315.77
  • 2) 53157.7
  • 3) 531.577
  • 4) 5.31577

Solution

5315.77
Q22. If 12.543 is distributed in 100 parts, then each part equals
  • 1) 1.2543
  • 2) 125.43
  • 3) 1254.3
  • 4) 0.12543

Solution

Thus, each part equals 0.12543.
Q23. Reduce to lowest form and check which fraction is greater out of the following pair of fractions: (a)      (b)

Solution

(a) ; Converting them into like fractions, we have , Since 14 > 11, we have Thus, (b) ; Converting them into like fractions, we have , Since -12 > -25, we have Thus,
Q24. If the cost of pen is Rs 12.75 then the cost of 5 such pens is:
  • 1) Rs 63.50
  • 2) Rs 63.75
  • 3) Rs 63.25
  • 4) Rs 63.00

Solution

Total cost = Rs 12.75 x 5 = Rs 63.75
Q25. Express the following fractions in the decreasing order of magnitude: 3 3 over 5 space comma space fraction numerator minus 8 over denominator 14 end fraction comma space 4 1 half comma 19 over 38 comma 6 1 half comma fraction numerator minus 22 over denominator 110 end fraction

Solution

In order to arrange the given fractions in decreasing order, we have to convert them into like fractions. ,   4 1 half equals 9 over 2  , 6 1 half equals 13 over 2, Now, LCM of 5, 7, 2, 2, 2, 5 is 70. Converting them into like fractions, we get , , , , , Since, 455 > 315 > 252 > 35 > -14 > -40 Decreasing order: Thus, 6 1 half space greater than space 4 1 half space greater than space 3 3 over 5 space greater than 19 over 38 space greater than space fraction numerator minus 22 over denominator 110 end fraction space greater than thin space fraction numerator minus 8 over denominator 14 end fraction 
Q26. In a class of 40 students, part of the students play cricket,of the remaining play football. How many students are playing in all?

Solution

Total students in the class = 40 Fraction of students playing Cricket = × 40 = = 10 students Thus, 10 students are playing cricket. Remaining students = 40 - 10 = 30 students Fraction of students playing football = × 30= 12students Thus, 12 students are playing football. Hence, total number of students who are playing = 10 + 12 = 22 students.
Q27. Rani poured 0.75 l of curd in a glass and added 1.25 l of water in it to make a buttermilk. She drank 0.5 l of buttermilk from it. How much litres of buttermilk is left in glass?  

Solution

Here, we need to add the quantity of curd and water in glass and then subtract the quantity drank by Rani. Curd added in glass = 0.75 l Water added in glass = 1.25 l Thus, Quantity in glass = 0.75 + 1.25 = 2.00 l Quantity of Buttermilk drank by Rani = 0.5 l Thus, Quantity of buttermilk left in glass = Quantity in glass - Quantity drank by Rani = 2.00 - 0.50 = 1.50 l  
Q28. Find the sum of the following fractions : (a) (b)

Solution

Fractions can be added only if they are like fractions. In that case, we can combine both the fractions by adding the numerators and write the common denominator just once. (a) = = (b) , Here we can convert the first fraction into lowest form = = = =
Q29. A football player advances of a yard. A second player in the same team advancesof a yard. How much more yard did the second player advance than the first player?

Solution

Here, we need to perform subtraction. Comparing and , we get and Since, 15 > 8 > the second player is leading. Thus, = Thus, the second player advances by  yard than the first player.
Q30. Clara's sister works in an American company in, Texas. She works forty-five hours every week and is paid $12.82 per hour. She sends three-tenths of her weekly salary to Clara to take care of their mother. How much money does Clara's sister send home each week?  

Solution

Given that, Clara's sister works for 45 hrs in a week   Amount of money she earns in an hr = $12.82   Thus, total money earned in a week = $12.82 x 45   = $576.90   Money send to her family = of her weekly salary   = x $576.90   (When a no. is divided by 10, 100, 1000,….,etc., we move the decimal place to the left, as many steps as there are zeroes over 1 in the denominator.)   Thus, = 0.3   So, money send = 0.3 x $576.90   = $173.07     Thus, Clara's sister sends home, $173.07 in a week.  

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