Q1. In ΔABC shown below, AD
BC, BE
AC and AD = BE. Prove that AE = BD.


Solution
Given :AD
BC, BE
AC and
AD = BE
To prove:AE = BD
Proof:
ADB =
BEA(right angles)
AB = AB(common)
AD = BE(given)
Thus,
ABD 
BAE(By RHS congruence rule).
Hence,BD = AE(Since, corresponding parts of congruent triangles are equal)
ADB =
BEA(right angles)
AB = AB(common)
AD = BE(given)
Thus,
Q2. Rectangles R1 and R2 are congruent, R1 has an area of 45 cm2 and length 9 cm. So, R2 will have length and breadth as _____, respectively.
Solution
Congruent rectangles have corresponding length and breadth equal.
Area of R1 = 45 = 9 × 5 = length × breadth = Area of R2
∴ R2 will have length and breadth as 9 cm and 5 cm, respectively.
Q3. Given below are measurements of some parts of pair of triangles which of the pair of two triangles are congruent to each other.
Solution

Q4. In the adjoining figure, if AB = PQ and BC = CQ, then find the measure of angle CPQ. 
Solution
In triangles ABC and PQC, we have:
AB = PQ
BC = CQ
B =
Q
Thus, triangles ABC and PQC are congruent.
Therefore,
BAC =
CPQ
Now, applying angle sum property in triangle ABC, we get,
BAC = 180o - 70o- 30o = 80o
Therefore,
CPQ = 80o
B =
Q
Thus, triangles ABC and PQC are congruent.
Therefore,
BAC =
CPQ
Now, applying angle sum property in triangle ABC, we get,
BAC = 180o - 70o- 30o = 80o
Therefore,
CPQ = 80o
Q5. In ∆STU and ∆PQR, ST = 5, TU = 6 and SU = 7. What is the measure of RP?
Solution
Adequate data is not available. ∆STU ≅ ∆PQR is not given.
Q6.
Given below are two triangles ABD and CBD. AD = CD and
∠3 = ∠4. Prove that DB bisects ∠ABC.
Solution
Q7. Name all the corresponding parts of the congruent figures given below: 

Solution
Given that, both the figures are congruent.Corresponding sides: OP
WX; OR
UX; QR
UV; QP
VW Corresponding vertices: O
X; P
W; Q
V; R
U Corresponding angles:

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